题目链接:https://leetcode.cn/problems/4sum/
核心方法:双指针
解析:比”Day12 - 15. 三数之和“多了一个移动的下标 j
class Solution:
def fourSum(self, nums: List[int], target: int) -> List[List[int]]:
nums.sort()
n = len(nums)
result = []
for i in range(n):
if i > 0 and nums[i] == nums[i-1]:
continue
for j in range(i+1,n):
if j > i + 1 and nums[j] ==nums[j-1]:
continue
left,right = j+1,n-1
while left < right:
s = nums[i] + nums[j] + nums[left] + nums[right]
if s == target:
result.append([nums[i],nums[j],nums[left],nums[right]])
while left < right and nums[left] == nums[left+1]:
left += 1
while left <right and nums[right] == nums[right-1]:
right -= 1
left += 1
right -= 1
elif s < target:
left += 1
else:
right -= 1
return result